Fractions in Disguise

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CLASS VIII Mathematics ~4–5 marks Ch 8 of 14
Fractions in Disguise

Class 8 · Mathematics · NCERT chapter notes · Akanksha Classes

Snapshot
  • The "fractions in disguise" of this chapter are percentages — a percentage is just a fraction whose denominator is fixed at 100. So $25\% = \dfrac{25}{100}$.
  • Fraction → percentage: multiply by $100$. Percentage → fraction: put it over $100$ and simplify. Percentage → decimal: divide by $100$. These three forms — Fraction, Decimal, Percentage — are the FDP trio.
  • $y\%$ of a quantity $Q$ means $\dfrac{y}{100}\times Q$. Percentages let us compare proportions fairly even when the wholes are different.
  • Used everywhere: profit/loss, discount, GST, interest, growth and decline. Profit% / Loss% are always on the cost price; increase/decrease% are always on the original (base) value.
  • Percentages can be more than 100% (achieving 120% of a target = 1.2 times it). Board weightage: ~4–5 marks — a percentage-of-quantity sum, and a profit/discount or increase/decrease word problem.
Detailed notes

1. What "per cent" really means

You hear it daily: "Mega Sale — up to 50% off!", "Hiya scored 83% in her exams". The symbol % is read per cent, from the Latin per centum = "out of a hundred". So $25\%$ means 25 out of every 100 — 25 marks out of 100, 25 rupees out of 100, and so on.

This gives the single most important idea of the chapter:

A percentage is a fraction with denominator 100: $\;\;y\% = \dfrac{y}{100}.$
Examples: $20\% = \dfrac{20}{100}=\dfrac15,\qquad 33\% = \dfrac{33}{100}.$

"50% of a quantity $s$" therefore means $50\times\dfrac{1}{100}\times s = \dfrac{50}{100}s = \dfrac12 s$ — exactly half. Percentages are fractions in disguise: that is the title of the chapter.

2. Turning a fraction into a percentage

To write a fraction as a percentage, find the equivalent fraction with 100 as the denominator — or, more simply, just multiply the fraction by 100.

  • Method 1 (equivalent fraction): $\dfrac34 = \dfrac{3\times25}{4\times25}=\dfrac{75}{100}=75\%.$
  • Method 2 (multiply by 100): set $\dfrac34=\dfrac{x}{100}\Rightarrow x=\dfrac34\times100 = 75$, so $75\%.$
A fraction is "of a unit", a percentage is "per 100". So to convert: $\;\;\dfrac{a}{b}\times100\;\%.$
NCERT Example — red paint in a mixture

Surya's orange mix is $\dfrac34$ red. As a percentage: $\dfrac34\times100=75\%$ red, so the yellow makes up $100-75=25\%$.

NCERT Example — Surya's savings $\dfrac25$

$\dfrac25 = \dfrac{2\times20}{5\times20}=\dfrac{40}{100}=40\%.$ Or directly $\dfrac25\times100 = 40\%.$ Both methods agree.

3. Turning a percentage into a fraction

Reverse the process: put the number over $100$ and simplify. A percentage $z\%$ equals any fraction equivalent to $\dfrac{z}{100}$.

NCERT Example — express 24% as a fraction

$24\% = \dfrac{24}{100} = \dfrac{12}{50}=\dfrac{6}{25}.$ All of $\dfrac{24}{100},\dfrac{12}{50},\dfrac{6}{25},\dfrac{48}{200}$ are correct equivalent forms.

Why 100 and not 10 or 1000? A biscuit with $\dfrac{9}{34}$ sugar vs $\dfrac{13}{45}$ sugar is hard to compare — but as $26.47\%$ vs $28.88\%$ the second is clearly sugary. We pick $100$ because our number system is base-10 (so $10,100,1000$ fit decimals neatly), and $100$ is the "sweet spot": large enough for detail, small enough to grasp mentally.

4. The FDP trio — Fraction, Decimal, Percentage

Every proportion has three faces. Converting between them is the workhorse skill of this chapter.

Percentage → Decimal: divide by $100$ (shift the point 2 places left). $\;50\% = 0.5,\;\;5\%=0.05.$
Decimal → Percentage: multiply by $100$. $\;0.7 = 70\%.$
Fraction ↔ Decimal: divide numerator by denominator. $\;\dfrac12=0.5.$
Per cent50%25%75%10%1%5%
Fraction$\tfrac12$$\tfrac14$$\tfrac34$$\tfrac{1}{10}$$\tfrac{1}{100}$$\tfrac{1}{20}$
Decimal0.50.250.750.10.010.05
NCERT Example — does 0.5 also give 50%?

Yes: $50\% = \dfrac{50}{100}=\dfrac12 = 0.5.$ So $50\%$ of $24 = \dfrac12\times24 = 0.5\times24 = 12$ — the fraction $\tfrac12$ and the decimal $0.5$ are the same tool wearing different clothes.

5. Percentage of a quantity

The central formula. $y\%$ of a quantity $Q$ means take $\dfrac{y}{100}$ of it:

$$y\%\text{ of }Q = \dfrac{y}{100}\times Q.$$
NCERT Example — sugar in biscuits (Madhu 120 g, 25%)

Madhu ate $120$ g of biscuits with $25\%$ sugar. Sugar $= \dfrac{25}{100}\times120 = 30$ g. Madhav ate $95$ g with $35\%$ sugar $= \dfrac{35}{100}\times95 = 33.25$ g. So Madhav ate more sugar.

Mental-maths shortcuts (used constantly):

  • $10\%$ = divide by $10$. $\;\;20\% = $ double of $10\%$. $\;\;5\% = $ half of $10\%$.
  • $25\% = \dfrac14$ (a quarter), $50\% = \dfrac12$, $75\% = \dfrac34$.
  • Handy identity: $20\% + 5\% = 25\%$, i.e. $\left(\dfrac{20}{100}Q\right)+\left(\dfrac{5}{100}Q\right)=\dfrac{25}{100}Q.$
NCERT Example — minimum marks for an A grade

Max marks $=75$; an A needs $80\%$. Minimum $= \dfrac{80}{100}\times75 = \dfrac45\times75 = 60$ marks (also $0.8\times75 = 60$).

6. Ratios → percentages, and "find the whole"

A ratio can be turned into a fraction, then a percentage.

NCERT Example — millet kanji, ratio 2 : 7

Millet : water $=2:7$, so millet is $\dfrac{2}{2+7}=\dfrac29$ of the mixture. As a percentage $\dfrac29\times100 = 22.22\%$ (water $=77.78\%$). In $500$ ml of mixture, millet $=22.22\%$ of $500 = 5\times22.22 = 111.1$ ml.

Sometimes the part is known and we want the whole. Use the proportional relationship $\dfrac{\text{percent}}{100}=\dfrac{\text{part}}{\text{whole}}$.

NCERT Example — cyclist, 40% is 92 km

$40\%$ of the journey is $92$ km, so $\dfrac{40}{100}=\dfrac{92}{d}\Rightarrow d = 92\times\dfrac{100}{40}=230$ km. Remaining distance $= 230-92 = 138$ km. (Mentally: $40\%$ is $92$, so $20\%$ is $46$, and $60\%$ is $138$.)

7. Percentages greater than 100%

A percentage can exceed $100$ — it just means "more than the whole". $200\%$ of a value is $2$ times it; $150\% = 1.5$ times; $250\% = 2.5$ times.

NCERT Example — sales target (target ₹5000)

Day 4 sales $= ₹6000$. Percentage of target $= \dfrac{6000}{5000}\times100 = \dfrac65\times100 = 120\%$. He achieved $120\%$ — i.e. $20\%$ more than the target.

NCERT Example — wheat harvest

Last year $260$ kg, this year $650$ kg. This year $= \dfrac{650}{260}\times100 = 250\%$ of last year — that is $2.5$ times the earlier harvest.

8. Comparing proportions fairly

You cannot compare two raw amounts when the wholes differ — convert both to percentages first. This is the whole point of percentages.

NCERT Example — Eesha's two tests

English $42/50$, Science $70/80$. As percentages: English $= \dfrac{42}{50}\times100 = 84\%$; Science $= \dfrac{70}{80}\times100 = 87.5\%$. Although she lost fewer marks in English, her Science score is the higher proportion — so she did better in Science.

Caution from the chapter: when comparing percentages, you are comparing proportions, not absolute values. A club that "grew $100\%$" may be tiny; a club that grew "$80\%$" may be huge — the base matters.

9. Percentage increase and decrease

For change over time, the percentage is always measured against the original (base) value.

$$\text{% increase} = \dfrac{\text{amount of increase}}{\text{original value}}\times100,\qquad \text{% decrease} = \dfrac{\text{amount of decrease}}{\text{original value}}\times100.$$
NCERT Example — tomato price rise

Price went ₹30 → ₹42, an increase of ₹12. $\text{% increase} = \dfrac{12}{30}\times100 = 40\%.$

NCERT Example — cinema footfall fall

Footfall $160\to100$, a decrease of $60$. $\text{% decrease} = \dfrac{60}{160}\times100 = 37.5\%.$

Two ways of saying the same thing: "population in 1991 is $165\%$ of 1961" $\equiv$ "population increased by $65\%$ from 1961 to 1991", because $q = p + 65\%\text{ of }p = 1.65p$.

10. Profit and loss

Three prices: Cost Price (CP) = what the seller paid; Marked Price (MP) = the quoted/MRP price; Selling Price (SP) = what the buyer finally pays.

  • If $\text{SP} > \text{CP}$: profit $= \text{SP}-\text{CP}$.
  • If $\text{SP} < \text{CP}$: loss $= \text{CP}-\text{SP}$.
Profit and loss percentages are taken on the cost price (CP $=100\%$):
$$\text{Profit%} = \dfrac{\text{Profit}}{\text{CP}}\times100,\qquad \text{Loss%} = \dfrac{\text{Loss}}{\text{CP}}\times100.$$
NCERT Example — Kishanlal's sweater

CP $= ₹300$, SP $= ₹430$. Profit $= 430-300 = ₹130$. $\text{Profit%} = \dfrac{130}{300}\times100 = 43.3\%.$

NCERT Example — Raghu's old rice

CP of 10 kg $= ₹350$, SP $= ₹300$. Loss $= 350-300 = ₹50$. $\text{Loss%} = \dfrac{50}{350}\times100 = 14.28\%.$

NCERT Example — damaged vase, 18% loss

CP $= ₹2650$, sold at $18\%$ loss. SP is $82\%$ of CP $= 0.82\times2650 = ₹2173.$ (Check: loss $= \dfrac{18}{100}\times2650 = 477$, and $2650-477 = 2173.$)

Note: "profit margin" here means gross profit (Sales − cost of goods). After subtracting other expenses you get net profit.

11. Discount and taxes (GST)

A discount of $30\%$ means the price is reduced by $30\%$ — so you pay $70\%$ of the marked price.

Discount worked example

MRP $= ₹1800$, discount $35\%$. SP $= 65\%$ of $1800 = 0.65\times1800 = ₹1170.$ If CP was $₹900$, profit $= 1170-900 = ₹270$, so $\text{Profit%} = \dfrac{270}{900}\times100 = 30\%.$

Taxes (GST, income tax) are stated as percentages. On a bill, GST is added on top of the price and goes to the government. E.g. a ₹450 item with $9\%$ CGST + $9\%$ SGST adds $40.50 + 40.50 = ₹81$, total ₹531.

NCERT "Tricky" — 30% + 20% vs 50% discount

On a ₹200 cake: "$30\%+20\%$" compounds — first $30\%$ off gives ₹140, then $20\%$ off ₹140 gives ₹112. A flat $50\%$ off gives ₹100. So $30\%+20\%\neq50\%$; the single $50\%$ discount is cheaper.

12. Interest — simple vs compound (growth)

Interest is extra money paid on a deposit (or loan). Principal $=$ amount deposited; rate $r$ is per annum (p.a.). After 1 year at rate $r$, the amount becomes principal $+ r\%$ of principal.

$$\text{Amount after 1 year} = P + r\%\text{ of }P = P\left(1+\dfrac{r}{100}\right).$$

Over $t$ years there are two cases:

  • No compounding (interest paid out each year): $\text{Amount} = P(1+rt)$, where $r$ is written as a decimal. Interest $=P\times r\times t.$
  • Compounding (interest added back, so it earns more next year): $\text{Amount} = P(1+r)^{t}.$
NCERT Example — ₹6000 at 10% p.a. for 3 years

Without compounding: interest each year $= 0.1\times6000 = ₹600$, so total $= 6000 + 3\times600 = ₹7800$ (gain $30\%$).

With compounding: $6000\times1.1\times1.1\times1.1 = 6000\times1.331 = ₹7986$ (gain $33.1\%$). Compounding always gives more.

13. Decline (depreciation)

Many items lose value over time — this is depreciation. A decrease of $r\%$ each period multiplies the value by $\left(1-\dfrac{r}{100}\right)$ each time.

NCERT Example — TV depreciates 5%

TV bought for ₹21000, drops $5\%$ in a year. New value $= 95\%$ of $21000 = 0.95\times21000 = ₹19950.$

NCERT Example — village population falling 10%/decade

Start $1250$, falls $10\%$ each decade $\Rightarrow$ multiply by $0.9$ each time: $1250\times0.9\times0.9\times0.9 = 911.25 \approx 910$ after 3 decades.

14. NCERT "Figure it Out" — selected solutions

Fractions as percentages: $\dfrac35 = 60\%$, $\dfrac{9}{20}=45\%$, $\dfrac{72}{150}=48\%$, $\dfrac13 = 33.33\%$.

Nandini's marbles: 15 white of 25 $\Rightarrow \dfrac{15}{25}\times100 = 60\%$ are white.

Walking to school: 15 of 80 walk $\Rightarrow \dfrac{15}{80}\times100 = 18.75\%.$

Values: $25\%$ of $160 = 40$; $16\%$ of $250 = 40$; $140\%$ of $40 = 56$; $1\%$ of 1 hour $= 1\%$ of $60$ min $= 0.6$ min; $7\%$ of $10$ kg $= 0.7$ kg.

Fill in the blanks: if $30\%$ of $k = 70$, then $60\%$ of $k = 140$, $90\% = 210$, $120\% = 280$ (since $10\%$ of $k = 70/3$). "3 is ___% of 300" $\Rightarrow 1\%$. "___ is $40\%$ of 4" $\Rightarrow 1.6$. "40 is $80\%$ of ___" $\Rightarrow 50$.

Halwa recipe (Rava 40%, Sugar 40%, Ghee 20%): for $2$ kg total, Rava $= 0.4\times2 = 0.8$ kg, Sugar $= 0.8$ kg, Ghee $= 0.2\times2 = 0.4$ kg.

Coffee pickers: $20\%$ takes $18$ days, so $100\%$ takes $5\times18 = 90$ days (assuming the work rate stays constant).

Badminton 10:80:10 of 90 min: warm-up $9$ min, play $72$ min, cool-down $9$ min.

Petrol ₹60 → ₹100: increase $= \dfrac{40}{60}\times100 = 66.66\%$ — option (iv).

A number increased by 20% becomes 90: $1.2\times n = 90\Rightarrow n = 75.$

Samson's car (₹4,40,000 after 15% discount): $85\%$ of original $= 440000\Rightarrow$ original $= 440000\times\dfrac{100}{85} = ₹5,17,647$ (approx).

15. Common mistakes to avoid

  • Taking profit/loss % on the selling price instead of the cost price (it's always on CP).
  • Treating "$30\% + 20\%$ off" as "$50\%$ off" — successive discounts compound, so they give a smaller total reduction.
  • Comparing two percentages as if equal-sized when the wholes (bases) differ.
  • Forgetting that a discount of $d\%$ means you pay $(100-d)\%$ of the marked price.
  • Confusing simple growth $P(1+rt)$ with compound growth $P(1+r)^t$.
  • Computing increase/decrease % on the new value instead of the original.

16. Quick revision checklist

  • $y\% = \dfrac{y}{100}$; fraction → % means $\times100$; % → decimal means $\div100$.
  • $y\%$ of $Q = \dfrac{y}{100}\times Q$.
  • Profit/Loss % on CP; increase/decrease % on the original value.
  • Discount of $d\%$ ⟹ pay $(100-d)\%$ of MP.
  • Growth: simple $P(1+rt)$, compound $P(1+r)^t$; decline ⟹ multiply by $(1-r)$ each period.
  • Percentages can exceed $100\%$ (e.g. $250\%$ = $2.5$ times).
Practice MCQs
1. $\dfrac34$ expressed as a percentage is:
  1. $34\%$
  2. $75\%$
  3. $43\%$
  4. $80\%$
Answer: (B) $\dfrac34\times100 = 75\%.$
2. $24\%$ written as a fraction in lowest terms is:
  1. $\dfrac{24}{10}$
  2. $\dfrac{12}{50}$
  3. $\dfrac{6}{25}$
  4. $\dfrac{24}{1000}$
Answer: (C) $\dfrac{24}{100}=\dfrac{6}{25}$ in simplest form.
3. $25\%$ of $160$ is:
  1. $25$
  2. $40$
  3. $64$
  4. $80$
Answer: (B) $\dfrac14\times160 = 40.$
4. The decimal form of $5\%$ is:
  1. $0.5$
  2. $5.0$
  3. $0.05$
  4. $0.005$
Answer: (C) $5\% = \dfrac{5}{100}=0.05.$
5. A shirt's price rises from ₹30 to ₹42. The percentage increase is:
  1. $12\%$
  2. $28\%$
  3. $40\%$
  4. $42\%$
Answer: (C) $\dfrac{12}{30}\times100 = 40\%$ (on the original ₹30).
6. An article costs ₹300 and is sold for ₹430. The profit percentage is about:
  1. $13\%$
  2. $30\%$
  3. $43.3\%$
  4. $130\%$
Answer: (C) profit $=130$, $\dfrac{130}{300}\times100 = 43.3\%$ (on CP).
7. A ₹1800 item has a $35\%$ discount. The selling price is:
  1. ₹630
  2. ₹1170
  3. ₹1450
  4. ₹1235
Answer: (B) pay $65\%$: $0.65\times1800 = ₹1170.$
8. If a sales target of ₹5000 is met with sales of ₹6000, the target achieved is:
  1. $60\%$
  2. $83\%$
  3. $120\%$
  4. $160\%$
Answer: (C) $\dfrac{6000}{5000}\times100 = 120\%$ — more than the whole.
9. A number increased by $20\%$ becomes $90$. The number is:
  1. $70$
  2. $72$
  3. $75$
  4. $108$
Answer: (C) $1.2\times n = 90\Rightarrow n = 75.$
10. ₹6000 at $10\%$ p.a. for 3 years, compounded annually, grows to:
  1. ₹7800
  2. ₹7986
  3. ₹8000
  4. ₹6600
Answer: (B) $6000\times1.1^3 = 6000\times1.331 = ₹7986.$
11. A "$30\% + 20\%$" discount on a ₹200 cake gives a final price of:
  1. ₹100
  2. ₹110
  3. ₹112
  4. ₹120
Answer: (C) $30\%$ off ⟹ ₹140; then $20\%$ off ₹140 ⟹ ₹112 (discounts compound).
12. Eesha scored $42/50$ in English and $70/80$ in Science. She did better in:
  1. English ($84\%$)
  2. Science ($87.5\%$)
  3. Equal
  4. Cannot compare
Answer: (B) $\dfrac{70}{80}\times100 = 87.5\% > 84\%.$
Assertion–Reason
A: A discount of $30\%$ then $20\%$ equals a flat $50\%$ discount.   R: Successive discounts simply add up.
Answer: Both A and R are false — successive discounts compound (multiply $0.7\times0.8 = 0.56$), giving a $44\%$ reduction, not $50\%$.
A: Profit percentage is calculated on the cost price.   R: The cost price is taken as the $100\%$ base for profit/loss.
Answer: Both A and R are true, and R correctly explains A.
Exam-style questions
Q1. A shopkeeper buys a geometry box for ₹75 and sells it for ₹110. Find his profit percentage with respect to cost. (3 marks)
Answer: Profit $= 110-75 = ₹35.$ $\text{Profit%} = \dfrac{35}{75}\times100 = 46.67\%.$
Q2. A clothing shop offers a $25\%$ discount on a shirt marked ₹300. How much does Anwar pay? (2 marks)
Answer: Pay $75\%$ of ₹300 $= 0.75\times300 = ₹225.$
Q3. The price of 1 kg rice was ₹38 in 2024 and ₹42 in 2025. Find the rate of inflation (percentage increase). (3 marks)
Answer: Increase $= 42-38 = ₹4.$ $\dfrac{4}{38}\times100 = 10.53\%$ (on the 2024 price).
Q4. The post office offers $7\%$ p.a. How much interest on ₹50,000 for 3 years without compounding, and how much more if compounded? (4 marks)
Answer: Without compounding: $50000\times0.07\times3 = ₹10500.$ With compounding: $50000\times1.07^3 = 50000\times1.225043 = ₹61252.15$, so interest $= ₹11252.15$ — about ₹752 more with compounding.
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