Measurement of Time and Motion

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CLASS VII Science ~7 marks/year Ch 8 of 12
Measurement of Time and Motion

Class 7 · Science · NCERT chapter notes · Akanksha Classes

Snapshot
  • Motion: an object is in motion if its position changes with time relative to a fixed point. Rest and motion are relative.
  • Time was measured in the past by sundials, water clocks (clepsydra), sand clocks and the swinging of a pendulum; today we use clocks and watches.
  • A simple pendulum takes a fixed time for one swing; the time for one complete to-and-fro swing is its time period.
  • The SI unit of time is the second (s); 1 minute = 60 s, 1 hour = 3600 s. The SI unit of distance is the metre (m).
  • Speed = distance ÷ time. SI unit of speed is metre per second (m/s); we also use km/h.
  • Uniform motion: equal distances in equal time intervals. Non-uniform motion: unequal distances in equal time intervals.
  • Motion can be shown on a distance–time graph; a straight slanting line means uniform motion, a horizontal line means the object is at rest.
  • Weightage: ~7 marks/year — 1-mark unit questions, numericals on speed, 2–3 mark pendulum and graph questions.
Detailed Notes

1. Rest and Motion

When the position of an object changes with time with respect to a fixed point (a reference point), the object is said to be in motion. If its position does not change, it is said to be at rest.

Motion = a change in the position of an object with time, measured with respect to a reference point. An object whose position does not change is at rest.

Rest and motion are relative. A passenger sitting in a moving train is at rest with respect to the train and to fellow passengers, but is in motion with respect to a person standing on the platform. So whether a body is at rest or in motion depends on the observer's reference point.

1.1 Types of motion

  • Rectilinear (linear) motion: motion along a straight line, e.g. a car on a straight road, a falling stone.
  • Circular motion: motion along a circular path, e.g. the tip of a clock's hand, a stone whirled on a string.
  • Periodic (oscillatory) motion: motion that repeats after a fixed time, e.g. the swing of a pendulum, a child on a swing.

2. The Need to Measure Time

People have always needed to measure time — to know when to sow crops, when to start a journey or when to gather. Early humans used events in nature that repeated regularly.

  • The Sun: day and night, sunrise and sunset, and the changing length of shadows gave a sense of time.
  • The Moon: the repeating phases of the Moon marked the month.
  • The seasons: the repeating cycle of seasons marked the year.

Any event that repeats itself after a fixed interval can be used to measure time. This idea is the heart of every clock.

3. Early Time-Measuring Devices

Before modern clocks, several clever devices were used.

  • Sundial: the position of the shadow of a fixed rod (gnomon) on a marked dial tells the time of day. It works only in sunlight.
  • Water clock (clepsydra): water drips at a steady rate from one vessel to another; the level of water shows how much time has passed.
  • Sand clock (hourglass): sand flows through a narrow neck from the upper to the lower bulb in a fixed time.
  • Candle clock: a marked candle burns down at a steady rate, the markings showing the time.

A great step forward came when it was discovered that a swinging pendulum keeps very regular time, which led to the pendulum clock.

4. The Simple Pendulum

A simple pendulum is a small heavy ball (called the bob) hung by a light thread from a fixed support. When pulled to one side and released, it swings to and fro about its central (rest) position.

One oscillation = one complete to-and-fro swing of the pendulum (from one extreme back to the same extreme). The time taken for one oscillation is called the time period of the pendulum.
NCERT Activity — Finding the time period of a pendulum

Set up a pendulum and let it swing with a small amplitude. Using a stopwatch, measure the time taken for 20 oscillations. Suppose it takes 40 seconds. Then the time for one oscillation (the time period) = total time ÷ number of oscillations = 40 ÷ 20 = 2 seconds. Measuring 20 swings and dividing reduces the error compared with timing a single swing.

A very important fact: the time period of a given pendulum is constant — it does not depend on how far you pull the bob (for small swings) or on the mass of the bob. It depends mainly on the length of the thread: a longer pendulum has a larger time period (swings more slowly). Because the swing is so regular, the pendulum became the basis of accurate clocks.

5. Units of Time

The SI unit of time is the second (s). Larger units are built from it.

1 minute = 60 seconds  |  1 hour = 60 minutes = 3600 seconds  |  1 day = 24 hours.

Very small intervals are measured in milliseconds (a thousandth of a second) and microseconds. Modern quartz and atomic clocks measure time extremely accurately, far better than any pendulum clock.

6. Speed — How Fast is an Object Moving?

Different objects move at different rates. A cheetah runs much faster than a person walking. The quantity that tells us how fast an object moves is called its speed.

Speed = distance travelled ÷ time taken. In symbols, speed = distance / time. The SI unit of speed is metre per second (m/s); another common unit is kilometre per hour (km/h).

6.1 Worked numericals

Worked example 1 — Finding speed

A car travels a distance of 240 km in 4 hours. Find its speed.
Speed = distance ÷ time = 240 km ÷ 4 h = 60 km/h.
So the car covers 60 km in every hour.

Worked example 2 — Finding distance

A boy walks at a speed of 5 m/s for 30 seconds. How far does he go?
Distance = speed × time = 5 m/s × 30 s = 150 m.

Worked example 3 — Finding time

A train moves at 72 km/h. How long does it take to cover 360 km?
Time = distance ÷ speed = 360 km ÷ 72 km/h = 5 hours.

6.2 Converting km/h to m/s

To convert km/h into m/s, multiply by 1000/3600, i.e. divide by 3.6. Example: 36 km/h = 36 ÷ 3.6 = 10 m/s.
Worked example 4 — Unit conversion

Convert 90 km/h into m/s.
90 km/h = 90 ÷ 3.6 = 25 m/s. (Check: 90 km = 90000 m and 1 h = 3600 s, so 90000 ÷ 3600 = 25 m/s.)

7. Uniform and Non-Uniform Motion

Depending on whether the speed stays the same, motion is of two kinds.

  • Uniform motion: the object covers equal distances in equal intervals of time; its speed is constant. Example: a car moving at a steady 60 km/h on a clear highway.
  • Non-uniform motion: the object covers unequal distances in equal intervals of time; its speed keeps changing. Example: a bus in city traffic, speeding up and slowing down.

For non-uniform motion, we often talk about the average speed, which is the total distance travelled divided by the total time taken.

Worked example 5 — Average speed

A cyclist covers 30 km in the first 2 hours and 10 km in the next 1 hour. Find the average speed.
Total distance = 30 + 10 = 40 km. Total time = 2 + 1 = 3 h.
Average speed = 40 ÷ 3 = 13.3 km/h (approximately).

8. Distance–Time Graphs

The motion of an object can be shown clearly on a distance–time graph. Time is taken along the horizontal axis (x-axis) and distance along the vertical axis (y-axis).

  • For an object at rest, the distance does not change, so the graph is a horizontal straight line.
  • For an object in uniform motion, equal distances are covered in equal times, so the graph is a straight slanting (inclined) line.
  • For non-uniform motion, the graph is a curved line.
On a distance–time graph, a steeper line means a higher speed. A straight slanting line shows uniform speed; a horizontal line shows the object is at rest.
Reading a graph — finding speed

Suppose a distance–time graph is a straight slanting line showing that an object covers 100 m in 20 s. The speed is found from the slope: speed = distance ÷ time = 100 ÷ 20 = 5 m/s. Because the line is straight, the speed is the same throughout — the motion is uniform.

Graphs help us compare two objects: the line with the greater slope (steeper line) belongs to the faster object. Graphs are widely used in science because they show at a glance how a quantity changes.

Practice MCQs
1. An object is said to be in motion if, with time, its:
  1. Colour changes
  2. Position changes with respect to a reference point
  3. Mass changes
  4. Temperature changes
Answer: (B) Motion means a change in position of an object with time, measured with respect to a fixed reference point.
2. The SI unit of time is the:
  1. Minute
  2. Hour
  3. Second
  4. Day
Answer: (C) The second (s) is the SI unit of time. 1 minute = 60 s and 1 hour = 3600 s.
3. The time taken for one complete to-and-fro swing of a pendulum is called its:
  1. Amplitude
  2. Frequency
  3. Time period
  4. Speed
Answer: (C) One complete to-and-fro swing is one oscillation, and the time for it is the time period of the pendulum.
4. A car travels 150 km in 3 hours. Its speed is:
  1. 30 km/h
  2. 50 km/h
  3. 75 km/h
  4. 450 km/h
Answer: (B) Speed = distance ÷ time = 150 ÷ 3 = 50 km/h.
5. The SI unit of speed is:
  1. km/h
  2. m/s
  3. cm/s
  4. m/min
Answer: (B) Since the SI unit of distance is the metre and of time the second, the SI unit of speed is metre per second (m/s).
6. A speed of 36 km/h is equal to:
  1. 6 m/s
  2. 10 m/s
  3. 36 m/s
  4. 360 m/s
Answer: (B) To convert km/h to m/s divide by 3.6: 36 ÷ 3.6 = 10 m/s.
7. In uniform motion, an object covers:
  1. Unequal distances in equal time intervals
  2. Equal distances in equal time intervals
  3. No distance at all
  4. Equal distances in unequal time intervals
Answer: (B) Uniform motion means equal distances in equal time intervals, so the speed stays constant.
8. Which device uses the dripping of water to measure time?
  1. Sundial
  2. Sand clock
  3. Water clock (clepsydra)
  4. Pendulum clock
Answer: (C) A water clock or clepsydra measures time by the steady dripping of water from one vessel to another.
9. The time period of a simple pendulum depends mainly on:
  1. The mass of the bob
  2. How far it is pulled (for small swings)
  3. The length of the thread
  4. The colour of the bob
Answer: (C) For small swings, the time period depends mainly on the length of the thread; a longer pendulum swings more slowly.
10. On a distance–time graph, an object at rest is shown by a:
  1. Straight slanting line
  2. Horizontal straight line
  3. Curved line
  4. Vertical straight line
Answer: (B) If an object is at rest, the distance does not change with time, so the graph is a horizontal straight line.
11. A pendulum makes 20 oscillations in 30 seconds. Its time period is:
  1. 0.5 s
  2. 1.5 s
  3. 2 s
  4. 20 s
Answer: (B) Time period = total time ÷ number of oscillations = 30 ÷ 20 = 1.5 s.
12. A boy runs at 4 m/s for 25 s. The distance he covers is:
  1. 29 m
  2. 50 m
  3. 100 m
  4. 625 m
Answer: (C) Distance = speed × time = 4 × 25 = 100 m.
13. On a distance–time graph, a straight slanting line represents:
  1. An object at rest
  2. Uniform motion
  3. Non-uniform motion
  4. No motion at all
Answer: (B) A straight slanting line means equal distances are covered in equal times, i.e. uniform motion at constant speed.
14. A passenger sitting in a moving train is at rest with respect to:
  1. A person standing on the platform
  2. Trees outside the train
  3. Fellow passengers in the same train
  4. A bird flying past
Answer: (C) Relative to fellow passengers and the train, the passenger's position does not change, so he is at rest with respect to them.
15. The motion of the tip of a clock's second hand is an example of:
  1. Rectilinear motion
  2. Circular motion
  3. Random motion
  4. No motion
Answer: (B) The tip of the hand moves along a circular path, so it shows circular motion.
Important Questions
Q1. Define speed and give its SI unit. A scooter covers 120 km in 3 hours; find its speed. (3 marks)
Answer: Speed is the distance travelled by an object in unit time; speed = distance ÷ time. Its SI unit is metre per second (m/s). For the scooter, speed = 120 km ÷ 3 h = 40 km/h.
Q2. What is a simple pendulum? Define its time period. (2 marks)
Answer: A simple pendulum is a small heavy bob suspended by a light, inextensible thread from a fixed support; when displaced and released it swings to and fro. The time taken by the pendulum to complete one full to-and-fro swing (one oscillation) is called its time period.
Q3. Distinguish between uniform and non-uniform motion with one example each. (2 marks)
Answer: In uniform motion, an object covers equal distances in equal intervals of time, so its speed is constant — for example, a car moving steadily at 60 km/h on a clear road. In non-uniform motion, an object covers unequal distances in equal intervals of time, so its speed keeps changing — for example, a bus moving through busy city traffic.
Q4. A pendulum takes 50 seconds to complete 25 oscillations. Find its time period. (2 marks)
Answer: Time period = total time ÷ number of oscillations = 50 s ÷ 25 = 2 seconds. Measuring many oscillations and dividing gives a more accurate value than timing a single swing.
Q5. Describe how a distance–time graph shows whether an object is at rest, in uniform motion, or in non-uniform motion. (3 marks)
Answer: On a distance–time graph, time is plotted on the x-axis and distance on the y-axis. If the object is at rest, the distance stays the same, so the graph is a horizontal straight line. If the object is in uniform motion, equal distances are covered in equal times, so the graph is a straight slanting line. If the object is in non-uniform motion, its speed keeps changing, so the graph is a curved line. A steeper line means a higher speed.
Q6. Convert 72 km/h into m/s and explain why the conversion factor is 1000/3600. (2 marks)
Answer: 1 km = 1000 m and 1 hour = 3600 s, so 1 km/h = 1000/3600 m/s = 1/3.6 m/s. To convert km/h to m/s we therefore divide by 3.6. Hence 72 km/h = 72 ÷ 3.6 = 20 m/s.
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